Question

Решите неравенство f'(x)⩽0
f(x) = x^4 - 2 x^3 + 3

Answer 1

f'(x)=(x^4 - 2 x^3 + 3)'
f'(x)=4x³-2*3x²=4x³-6x²
4x³-6x²≤0
4x²(x-1.5)≤0
x≤1.5
x∈(-∞; 1.5]