Question

Пожжжжжжалуйста )))))

Answer 1

$3x^2-2x-5 textgreater 0 \ D=(-2)^2+5*3*4=4+60=64 \ x_{1,2} = frac{2б8}{6} \ x_1 = 10/6 ; x_2 = -1 \ x in (-infty;-1) cup (frac{10}{6};+infty) \ \ x^2+6x+9 textless 0 \ D=6^2-4*9=0 \ x = frac{-6}{2} = -3 \ (x+3)^2 textless 0 \ x in emptyset \ \ -x^2+6x geq 0 \ x(-x+6) geq 0 \ x=0;x=6 \ x in [0;6]$