Question

Log 12 48 если lg2=a lg3=b

Answer 1

log₁₂48   lg2=a   lg3=b
log₁₂48=lg48/lg12=lg(16*3)/lg(4*3)=(lg2⁴+lg3)/(lg2²+lg3)=
=(4*lg2+lg3)/(2*lg2+lg3)=(4a+b)/(2a+b).