Question

2sin6xcos2x=sin8x+1
Срочно

Answer 1

$2sin6xcos2x=sin8x+1$

$sin8x+sin4x=sin8x+1$

$sin4x=1$

$4x=frac{pi}{2}+2pi n$

$x=frac{pi}{8}+ frac{pi}{2}n$

n - целые