Question

Sin 3 π/4=
Cos 3π/4=
Tg 3π/4=
Ctg 3π/4=

Answer 1

sin(π-π/4)=sinπ/4=√2/2
cos(π-π/4)=-cosπ/4=-√2/2
tg(π-π/4)=-tgπ/4=-1
ctg(π-π/4)=-ctgπ/4=-1

Answer 2

sin(π-π/4)=sinπ/4=√2/2
cos(π-π/4)=-cosπ/4=-√2/2
tg(π-π/4)=-tgπ/4=-1
ctg(π-π/4)=-ctgπ/4=-1

Answer 3

А разве не так все написано? Зачем дублировать?

Answer 4

XD