Question

(2x+3)(2x+3)-4(1-x)^2=1

Answer 1

4x²+6x+6x+9-4(1-2x+x²)-1=0
4x²+12x+9-4+8x-4x²-1=0
20x+4=0
20x=-4
x=-4/20
x=-1/5

Answer 2

(2x+3)(2x+3)-4(1-x)^2=14x^2+12x+9-4+8x-4x^2=120x=-5+1
x=-4/20
x=1/5
x=-0,2