Question

c 2, срочно заранее спасибо

Answer 1

$left { {{log_{sqrt{3}}(y-x) = 2} atop {3^x*4^y = 768}} right. \ log_3(y-x) = 1 \ left { {{y-x=3 = textgreater y =x+3} atop {3^x*4^y = 768}} right. \ 3^x*4^{x+3} = 768 \ 3^x*4^3*4^x = 768 \ 3^x*4^x = 12 \ (3*4)^x = 12 \ x = 1 \ y = 3 + 1 = 4$

Answer 2

спасибо