Question

решите уравнение log1/4(x^2+6x)=-2

Answer 1

$log_{ frac{1}{4}}(x^2 + 6x) = -2 \ - frac{1}{2}log_2(x^2 + 6x) = -2 | *(-2) \ log_2(x^2 + 6x) = 4 \ x^2 + 6x = 16 \ x^2 + 6x - 16 \ D = 36 + 64 = 100 \ x_1 = frac{-6 + 10}{2} = 2 \ x_2 = frac{-6-10}{2} = -8$