Question

Прошу помощи, нужно 3 и 5 задание

Answer 1

3.  5cos(β/2)-4ctg(β/2)*sin(β/2)=5cos(β/2)-4*(cos(β/2)/sin(β/2))*sin(β/2)=5cos(β/2)-4cos(β/2)=cos(β/2)

5. tg⁵α*cos³α/(1+tg²α)=(sinα/cosα)⁵*cos³α/(1/cos²α)=(sinα/cosα)⁵ *cos³α*cos²α=(sinα/cosα)⁵ *cos⁵α=sin⁵α