Question

Вычислить:
1)√128/√8;
2)4√40/√10;
3)20√18/5√2

Answer 1

1) √128/√8 = √(128/8) = √(16/1) = √16 = 4.
2) 4√40/√10 = √640/√10 = √(640/10) = √64 = 8.
3) 20√18/5√2 = 4√18/√2 = √288√2 = √(2882) = √144 = 12.