Question

решите уравнение (x-3)²+(x+4)²-(x-5)²=17×+24

Answer 1

$(x-3)^2+(x+4)^2-(x-5)^2=17x+24\x^2-6x+9+x^2+8x+16-x^2+10x-25=17x+24\x^2-5x-24=0\D=25+4cdot24=25+96=121=(11)^2\x_{1,2}=frac{5pm11}{2}\x_1=8,;x_2=-3$