Question

log_4^(x+3)-log_4^(x-1)=2 - log_4^8

Answer 1

log₄(x+3)-log₄(x-1)=log₄16-log₄8;
log₄((x+3)/(x-1))=log₄(16/8);
(x+3)/(x-1)=2; *(x-1)
x+3=2x-2;
x=5;