Question

Решите неравенство : а) х2 – 3х – 2< 0; б) – 2х2 + 5х + 3 0.

Answer 1

$x^2-3x-2 textless 0 \ D=(-3)^2-(-2)*4*1=9+2*4=9+8=17 \ x_{1,2} = frac{3бsqrt{17}}{2} \ ax^2; a textgreater 0 ; answer : (frac{3-sqrt{17}}{2};frac{3+sqrt{17}}{2})$