Question

1)sinx-√3/2cosx=0
2)sin^2x-3sinx*cosx+2cos^2x=0

Answer 1

делим на cos^2x3tg^2x+tgx-2=0D=1+24=25tgx=(-1-5)/6=-1   x=-pi/4+pi ntgx=2/3      x=arctg2/3+pi k