Question

sinx cosx - корень 3 cos^2x=0

Answer 1

$sinxcosx-sqrt3cos^2x=0\cosx(sinx-sqrt3cosx)=0\\1)cosx=0\x=frac{pi}{2}+pi n, ; nin Z;\\2)sinx-sqrt3cosx=0|:cosx\tgx-sqrt3=0\tgx=sqrt3\x=arctgsqrt3+pi n\x=frac{pi}{3}+pi n, ; nin Z$