Question

a^3+27 и (y^3-16y)/(2y+18)*(y^2+9y)(4-y)

Answer 1

$a^3+27=(a+3)(a^2-3a+9)$

$frac{(y^3-16y)}{(2y+18)*(y^2+9y)(4-y)}=frac{y(y-4)(y+4)}{2(y+9)y(y+9)(4-y)}=-frac{y+4}{2y^2+36y+162}$