Question

{x-5y=2
{x^2-y=10
Решите систему уравнений

Answer 1

x=2+5y
$(2+5y)^{2}-y=10$
$(4+20y+25y^{2})-y-10=25y^{2}+19y-6=0$
y1=-1, x1=-3
y2=$frac{6}{25}$, x2=3.2