Question

помогите решить 5.24

Answer 1

1) log(3) 27 - log(√3) 27 - log(1/3) 27 -log(√3/2)  64/27=
=log(3) 3^3  -  log(√3) (√3)^6  -log(1/3) (1/3)^(-3)  -  log(√3/2)  (√3/2)^(-6)=
=3-6-(-3)-(-6)=3-6+3+6=6