Question

Срочно!!!Помогите решить неравенства l3х-7l больше или равно 5,l2х-1l>5,заранее спасибо)

Answer 1

$|x| textgreater a; ; Leftrightarrow ; ; left [ {{x textgreater a} atop {x textless -a}} right. ; ; ; ; ; ; /////////; (-a)----(a)///////\\1); ; |3x-7| geq 5; ; to ; ; left [ {{3x-7 geq 5} atop {3x-7 leq -5}} right. ; left [ {{3x geq 12} atop {3x leq 2}} right. ; left [ {{x geq 4} atop {x leq frac{2}{3}}} right. \\xin (-infty ,frac{2}{3}, ]cup [, 4,+infty )$

$b); ; |2x-1| textgreater 5; ; to ; ; left [ {{2x-1 textgreater 5} atop {2x-1 textless -5}} right. ; left [ {{2x textgreater 6} atop {2x textless -4}} right. ; left [ {{x textgreater 3} atop {x textless -2}} right. \\xin (-infty ,-2)cup (3,+infty )$