Question

Разложите на множители многочлен (3xy+1)(3x+y)-y(3x+y)в квадрате

Answer 1

$(3xy+1)(3x+y)-y(3x+y)^2=(3x+y)(3xy+1-3xy-y^2)$=

= $(3x+y)(1-y^2)=(3x-y)(1-y)(1+y)</var>$

 

 

Answer 2

(3xy+1)(3x+y)-y(3x+y)^2= (3x+y) (3xy+1-3xy-y^2) = (3x+ y) (1-y) (1+y)