Question

Помогите решить неравенство,пожалуйста
log5 log1/2 log9 x>0

Answer 1

$log_5(log_{1/2}(log_9(x)\ \textgreater \ 0 \\ log_{1/2}(log_9(x)\ \textgreater \ 5^0 \\ log_{1/2}(log_9(x)\ \textgreater \ 1 \\ log_9(x)\ \textgreater \ 1/2^1 \\ x\ \textgreater \ 9^(1/2) \\ x\ \textgreater \ 3 \\ (3; \infty)$