Question

lim 4x²-9/2x+3
x=> -3/2

Answer 1

$\lim_{n \to \-1,5} \frac{4x^{2}-9}{2x+3} = \frac{(2x+3)(2x-3)}{2x+3}=2x-3=2*(-1.5)-3=-6$

Answer 2

$\lim_{x \to \{-1,5} \frac{4x^2-9}{2x+3} = \frac{0}{0} \\ = \frac{4x^2-3^3}{2x+3} = \frac{(2x+3)(2x-3)}{2x+3}=2x-3=-6$
Лопиталем:
$\lim_{x \to \{-1,5} \frac{(4x^2-9)'}{(2x+3)'}= \frac{8x}{2}= (-1,5*8):2=-6$