Предмет: Геометрия, автор: зубарджат

площадь ромба18,сторона 6 найдите тупой угол

Ответы

Автор ответа: lys

0

S=a^2 * sin B(s-площадь..а-сторона ромба..sinB-синус острого угла)

зная данные наидем острый угол.

18=6^2 * sin B

sin B=12 =30 гр

тогда 180-30=150 . ответ: 150

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