Question

lim x^2-6x-16
x- - 2 x2+x-2

Answer 1

$\lim_{x \to -2 } \frac{x^2-6x-16}{x^2+x-2} = (\frac{0}{0} )= \lim_{x \to -2 } \frac{2x-6}{2x+1} = \frac{-4-6}{-4+1} = \frac{10}{3} .$