Question

помогите решить корень n степени

Answer 1

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Answer 2

$B3) 2\ \textless \ \sqrt[3]{19} \ \textless \ 3(8\ \textless \ 19\ \textless \ 27) \\ B4) \frac{ \sqrt{x}^2- \sqrt{2}^2 }{ \sqrt{x}+ \sqrt{2} } = \frac{( \sqrt{x} - \sqrt{2})( \sqrt{x} + \sqrt{2}) }{\sqrt{x} + \sqrt{2}} = \sqrt{x} - \sqrt{2} . \\ B5) \sqrt{ \frac{9}{4} }- \sqrt[3]{ \frac{27}{8} } = \frac{3}{2} - \frac{3}{2} =0.$
$B6) \sqrt[6]{x} =t: \\ 2t^2-5t-3=0, D=25+24=7^2 \\ t_1=3, t_2=-0,5 \\ \sqrt[6]{x} =3, x=3^6=729 \\ \sqrt[6]{x} =-0,5-resheniy net. Otvet: x=729.$