Question

Решите неравенство:
(x-6)^2<√10(x-6)

Answer 1

$(x-6)^2 textless sqrt{10} (x-6)\ (x-6)^2- sqrt{10}(x-6) textless 0\ (x-6)(x-6- sqrt{10}) textless 0\ \ (x-6)(x-6- sqrt{10})=0\ x_1=6\ x_2=6+ sqrt{10}$

___+___(6)___-__(6+√10)___+___

Ответ: $x in (6;6+ sqrt{10})$