Question

(x+1)(x+2)−(x+4)(x+8)=0

Answer 1

(x+1)*(x+2)-(x+4)*(x+8)=0
x²+2x+x+2-(x²+8x+4x+32)=0
x²+3x+2-x²-8x-4x-32=0
-9x=-2+32
-9x=30|:(-9)
x=-$3 frac{1}{3}$