Question

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Answer 1

х^2-5х+6=0 по теореме виета
х1+х2=5
х1*х2=6
х1=2
х2=3
х^2-12х+20=0
х1+х2=12
х1*х2=20
х1=10 х2=2
((х-2)(х-3))/((х-10)(х-2))=
(х-3)/(х-10)
lim=(2-3)(2-10)=1/8