Question

(2х-у)(4х^2+2ху+у^2)(8х^3+у^3)

Answer 1

$=(2x-y)(2x+y)(8x^3) =\ = (4x^2-y^2)(8x^3+y^3)= \ =32x^5+4x^2y^3-8x^3y^2-y^5= \ = 64x^6-y^6$