Question

решите срочно уравнение

Answer 1

$frac{y+3}{y-3}- frac{y-3}{y+3}=1.5 \ \ y neq 3 \ y neq -3$
(y+3)² - (y-3)² = 1.5(y-3)(y+3)
y² +6y+9 -(y² -6y+9)=1.5(y² -9)
y² +6y+9-y² +6y-9=1.5y² -13.5
-1.5y² +12y+13.5=0
y² - 8y - 9=0
D=64+36=100
y₁=(8-10)/2= -1
y₂=(8+10)/2=9

Ответ: -1;  9.

Answer 2

ОЗ (y-3)(y+3)≠0
y≠3
y≠-3
(y+3)²-(y-3)²=1,5(y²-9)
(y+3-y+3)(y+3+y-3)=1,5y²-13,5
12y=1,5y²-13,5
y²-8y-9=0
y1+y2=8 U y1*y2=-9
y1=-1
y2=9