Question

решите пожалуйста!!!!!!!!!!
 log2 (x+1)+2log4 (x+5) = 8log1/2 8 

Answer 1

Log2 (x+1) + 2log4 (x+5) = 8log1/2 8 Log2 (x+1) + 2/2log2 (X+5) = -8log2 8 Log2 (x+1) + log2 (x+5) = -8 * 3 Log2 (x+1)(x+5) = -24 Log2 x^2+5x+x+5= -24 X^2+6x+5 = 0 ; > 0 не равно 1 D=36-20=16=4^2 X1,2=1;5 1 не разрешено !