Question

3x в квадрате -x-4=0

Answer 1

$3x^{2} - x - 4=0 \ D= b^{2} -4ac= 1^{2} - 4 *3 *(-4)= 1+ 48 = 49 \ sqrt{D} = sqrt{49} =7 \ x1= frac{-b+ sqrt{D} }{2a} = frac{1+7}{6} = frac{8}{6} = frac{4}{3} = 1 frac{1}{3} \ x2= frac{-b- sqrt{D} }{2a} = frac{1-7}{6} = frac{-6}{6} = -1$

Ответ: $-1; 1 frac{1}{3}$