Question

$16^{1,25} * frac{1}{8}$

Answer 1

$(a^x)^y=a^{x*y} \ a^x*a^y=a^{x+y} \ frac{1}{a^x} =a^{-x} \ \ 16^{1,25} * frac{1}{8} \ 16=2^4 \ 8=2^3 \ (2^4)^{1.25}*2^{-3}=2^{4*1.25}*2^{-3}=2^5*2^{-3}=2^{5+(-3)}=2^2=4$