Question

x^6-x^4-x^2+1. Очень надо!
8b^3-1/27

Answer 1

x^6-x^4-x²+1=(x^6-x^4)-(x²-1)=x^4(x²-1)-(x²-1)=(x²-1)(x^4-1)=(x²-1)(x²-1)(x²+1)=(x²+1)·(x-1)²·(x+1)²
2) 8b³-127=(2b)³-(13)³=(2b-13)(4b²+(2b)3+19)