Question

Решите уравнение! Спасибо заранее!
log₄X+log₈X=5

Answer 1

log2(x)/log2(4) + log2(x)/log2(8) = 5                 (ОДЗ x >0)
1/2*log2(x) + 1/3*log2(x) = 5
5/6 * log2(x) = 5
1/6* log2(x) = 1
log2(x) = 6
x = 2^6
x = 64