Question

Решите уравнение
6 sin^2x+sin x * cos x - cos^2x=2

Answer 1

6sin^2x+sinxcosx-cos^2x-2sin^2x-2cos^2x=0
4sin^2x+sinxcosx-3cos^2x=0 :
cos^2x4tg^2x+tgx-3=0
tgx=-1
tgx=3/4
x=arctg3/4+Пk
x=-П/4+Пk