Question

решите уравнение: sin(2x-п/3)+1=0

Answer 1

$sin(2x - frac{ pi }{3}) + 1 = 0$

$-cos( frac{ pi }{6} + 2x) = -1 |*(-1)$

$cos( frac{ pi }{6} + 2x) = 1$

$frac{ pi }{6} + 2x = 2 pi n$

$2x = 2 pi n - frac{ pi }{6}$

$x = pi n - frac{ pi }{12}$ , $n$∈$Z$