Предмет: Математика, автор: Nika20058912

К 500 г 12%-го раствора соли добавили 300 г 8%-го раствора соли. Какова концентрация полученной смеси?

Ответы

Автор ответа: vlksm2007

В первом растворе масса соли равна: 500*0,12 = 60 грамм
Во втором растворе масса соли равна: 300*0,08 = 24 грамма
Всего соли: 60 + 24 = 84 грамма.
Масса всего раствора: 500 + 300 = 800 граммов
Концентрация равна: 84/800 = 0,105 или 10,5%

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