Question

помогите решить плиз

Answer 1

1) log₂log₅⁸√5=log₂log₅(5)¹/⁸=log₂(1/8*log₅5)=log₂(1/8)=log₂2⁻³
=(-3)*log₂2=-3;
2)log₃² log₁/₅(1/125)=log₃² log₁/₅(1/5)³=log₃²(3)=2;
3)log₄ log₃√81=log₄ log₃3⁴/²=log₄2=log(₂²)2=1/2;
4)log√₃ log₁/₅(1/125)=log√₃ log₁/₅(1/5)³=
=log₃¹/² 3=2;
5)log₈/₂₇ log₂₅125=log(₂/₃)³ log₅² 5³=1/3*log₂/₃ (3/2)=1/3;
6)log₁/₄(log₂3*log₃4)=log₂⁻²(1/log₃2)*2*log₃2=-1/2*log₂2=-1/2

Answer 2

огромное спасибо!