Question

x^2-4x+3=0 решите плз

Answer 1

x^2 - 4x + 3 = 0 
D = 16 - 12 = 4 = 2^2
x₁ = (4 + 2)/2 = 6/2 = 3;
x₂ = (4 - 2)/2 = 2/2 = 1; 

Answer 2

X^2-4x+3=0
D = b2 - 4ac = (-4)2 - 4·1·+3 = 16 - 12 = 4
x1 = (4 - √4) /2·1 = (4 - 2)/2 = 2/2 = 1
x2 = (4 + √4)/2·1 = (4 + 2)/2 = 6/2 = 3