Question

(x+2)квадрат-(y-2) квадрат =1

Answer 1

$x^{2} +4 x+4- y^{2} +4y-4=1, \ x^{2} +4 x- y^{2} +4y=1 \ x^{2} +4 x=y^{2} -4y \ x(x+4) =y(y -4), \ x=0, x=-4 \ y=0, y=4$