Question

Помогите решить уравнения прошу
1) (3х+1)^2 - (3х-1)^2 = 11х+ 1, 2
2) (5+2у)(у-3) -2 (у-1)^2 = 0

Answer 1

1) (3х+1)^2 - (3х-1)^2 = 11х+ 1, 2
9x^2 +6x  + 1 -(9x^2 - 6x +1) -11x -1.2 = 0
9x^2 +6x  + 1 -9x^2 + 6x -1 -11x -1.2 = 0
x -1.2 = 0
x = 1.2

2) (5+2у)(у-3) -2 (у-1)^2 = 0
5y -15 +2y^2 -6y -2(y^2 -2y +1) = 0
-y -15 +2y^2 - 2y^2 +4y -2 = 0
3y -17 =0
3y = 17
y = 17/3
y = 5  2/3

Answer 2

Спасиб :)