Question

а)1/2×(x+4/5)-(1/5-x)
б)-2/3×(6/7-y)+(2/7+y)
в)-(y+1/8)+3/4×(2+y)
г)1/9×(3/5-x)-(x-1/15)

Answer 1

а)1/2×(x+4/5)-(1/5-x)=0,5х+0,4-0,2+х=1,5х+0,2; /// б)-2/3×(6/7-y)+(2/7+y)=-4/7+2/3у+2/7+у=1 2/3у-2/7; /// в)-(y+1/8)+3/4×(2+y)=-у-1/8+3/2+3/4у=-1/4у+11/8=1 3/8-1/4у; //// г)1/9×(3/5-x)-(x-1/15)=1/15-1/9x-x+1/15=2/15-1 1/9x;