Question

(a¹²)⁸=
k*k⁸=
(k¹²)¹¹/k⁶⁹=
(c⁸)⁹/c³⁰=
(a¹²)⁸=
(c⁹)⁶*c⁴=
(d¹²)⁵*d¹⁵=
(k²)⁹*k⁸=
(k¹⁴)⁶/k³¹=
(k-3)¹²/(k-3)⁵=
решите все дам много балов

Answer 1

(а¹²)⁸= а ¹²*⁸= а ⁹⁶
к * к⁸=к¹  * к⁸= к⁹
(k¹²)¹¹/ k⁶⁹= k ¹³²⁻⁶⁹= k⁶³
(c⁸)⁹ / c ³⁰ = c ⁷²⁻³⁰= c ⁴²
(a ¹²)⁸= a ⁹⁶
(c⁹)⁶ * c⁴= c ⁵⁴⁺⁴= c ⁵⁸
(d¹²)⁵ * d¹⁵= d⁶⁰⁺¹⁵= d⁷⁵
(k²)⁹ *k⁸= k¹⁸⁺⁸= k²⁶
(k¹⁴)⁶ / k³¹= k⁸⁴⁻³¹=k⁵³
(k-3)¹² / (k-3)⁵ = (k-3)¹²⁻⁵ = (k-3)⁷