Question

найдите ординату общей точки графиков функций y=2^3x-1 *3^x-3 и y=4^x+1

Answer 1

2^(3x-1)*3^(x-3) = 4^(x+1)
2^(3x-1)*3^(x-3) = 2^(2x+2)|:2^(2x +2)
2^(3x-1)*3^(x-3) / 2^(2x+2)=1
2^(x-3)*3^(x-3) = 1
6^(x-3) = 6^0
x-3 = 0
x = 3
y = 4^(x+1) = 4^4 = 256  или  y = 2^(3x-1)*3^(x-3) = 2^8*3^0 = 256