Question

Задание 6, дам 25 баллов

Answer 1

я знаю только до 2 (( Сорри
$1) f(x)=x^2-2 \ f'(x)=2x-0=2x\\f'(2+sqrt{3})=2(2+sqrt{3})=4+2sqrt{3}=0+frac{1}{sqrt{x}} = frac{1}{sqrt{x}} \\f'(2-sqrt{3})=2(2-sqrt{3})=4-2sqrt{3}=0-frac{1}{sqrt{x}} = -frac{1}{sqrt{x}}\\f'(2+sqrt{3}) + f'(2-sqrt{3}) = frac{1}{sqrt{x}} + (-frac{1}{sqrt{x}}) = frac{1}{sqrt{x}} - frac{1}{sqrt{x}} = 0 \\2)\\2sqrt{17}=sqrt{2^2*17}=sqrt{4*17}=sqrt{68}=8.(24)\ 8,246... textgreater 8.(24)$