Question

СРОЧНО!!!!!!!!!! ПОМОГИТЕ РЕШИТЬ!!!!!!!!!!!!!!

Answer 1

решение в приложении.

Answer 2

(b-1)²·(1/(b-1)²+1/(b²-1)+2/(b+1))=(b-1)²·(1/(b-1)(b-1)+1/(b-1)(b+1))+2/(b+1)=
=(b-1)²·(1·(b+1)+1·(b-1))/(b-1))(b-1)(b+1)+2/(b+1)=
(b-1)²·(b+1+b-1)/(b-1)²(b+1)+2/(b+1)=
2b/(b+1)+2/(b+1)=(2b+2)/(b+1)=2(b+1)/(b+1)=2.