Question

Помогите пожалуйста,срочно

Answer 1

$frac{x^2-|x|-12}{x-3} geq 2x\\1); ; x geq 0; to ; |x|=x\\frac{x^2-x-12}{x-3} geq 2x; ,; frac{x^2-x-12-2x^2+6x}{x-3} geq 0; ,; frac{-x^2+5x-12}{x-3 } geq 0\\ frac{x^2-5x+12}{x-3} leq 0\\x^2-5x+12 geq 0; pri; xin R,; t.k.; D=24-48 textless 0; to \\x-3 textless 0; ,; x textless 3\\0leq x<3$

$2)x<0,|x|=-x\\ frac{x^2+x-12}{x-3} geq 2x ; ,; frac{x^2+x-12-2x^2+6x}{x-3} geq 0; ,; frac{-x^2+7x-12}{x-3} geq 0\\ frac{x^2-7x+12}{x-3} geq 0; ,; frac{(x-3)(x-4)}{x-3} geq 0; ,; x-4 geq 0; ,\\x geq 4; ; ne; podxodit,; t.k.; x textless 0\\Otvet:; 0 leq x textless 3; ; ili; ; xin [, 0,3).$