Предмет: Математика, автор: natfrance

Решить неравенство
$0.2^{x+3}$ ≥ 5

Ответы

Автор ответа: abror1998

0

0.2^(x+3)≥5
1/5(x+3)≥5
5^-(x+3)≥5^1
-(x+3)≥1
x+3≤-1
x≤-4

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