Question

НАЙТИ ЗНАЧЕНИЕ ПРОИЗВОДНОЙ ФУНКЦИИ f(X)=1-6∛Х В ТОЧКЕ Х0=8

Answer 1

$= frac{-2}{ sqrt[3]{ x^{2}}}$
х(0)=8
f'(8)=-1/2

Answer 2

f'(x) = (1-6∛x)' = 1' - (6∛x)' = 0-6 (x^1/3)' = -6*1/3 x^(1/3-1) = -2x^(-2/3)=

=$frac{-2}{ sqrt[3]{x^2} }$

f'(8) = $frac{-2}{ sqrt[3]{8^2} } = frac{-2}{ sqrt[3]{64} } = frac{-2}{4} = frac{-1}{2} =-0.5$